- 1 (4.64 KiB) Viewed 144 times
respectively.
Pr(N = n) = 0 ,n=0,1,2,... n!
1 (x-m )2 Px(x) = 202 V2πσ2
Pr(N = n) = 0 ,n=0,1,2,... n! 1 (x-m )2 Px(x) = 202 V2πσ2
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
Pr(N = n) = 0 ,n=0,1,2,... n! 1 (x-m )2 Px(x) = 202 V2πσ2
Show that the mean and variance of X are m and σ^2,
respectively.
Pr(N = n) = 0 ,n=0,1,2,... n!
1 (x-m )2 Px(x) = 202 V2πσ2
respectively.
Pr(N = n) = 0 ,n=0,1,2,... n!
1 (x-m )2 Px(x) = 202 V2πσ2
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!