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respectively.
Pr(N = n) = 0 ,n=0,1,2,... n!
1 (x-m )2 Px(x) = 202 V2πσ2
Pr(N = n) = 0 ,n=0,1,2,... n! 1 (x-m )2 Px(x) = 202 V2πσ2
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answerhappygod
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Pr(N = n) = 0 ,n=0,1,2,... n! 1 (x-m )2 Px(x) = 202 V2πσ2
Show that the mean and variance of X are m and σ^2,
respectively.
Pr(N = n) = 0 ,n=0,1,2,... n!
1 (x-m )2 Px(x) = 202 V2πσ2
respectively.
Pr(N = n) = 0 ,n=0,1,2,... n!
1 (x-m )2 Px(x) = 202 V2πσ2