6.4 Cache Memory EXAMPLE 6.3 Assume a byte-addressable memory consisting of 16 bytes divided into 8 blocks. Cache contai

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6 4 Cache Memory Example 6 3 Assume A Byte Addressable Memory Consisting Of 16 Bytes Divided Into 8 Blocks Cache Contai 1 (29.73 KiB) Viewed 43 times

6 4 Cache Memory Example 6 3 Assume A Byte Addressable Memory Consisting Of 16 Bytes Divided Into 8 Blocks Cache Contai 2 (29.73 KiB) Viewed 43 times

6 4 Cache Memory Example 6 3 Assume A Byte Addressable Memory Consisting Of 16 Bytes Divided Into 8 Blocks Cache Contai 3 (36.29 KiB) Viewed 43 times

6.4 Cache Memory EXAMPLE 6.3 Assume a byte-addressable memory consisting of 16 bytes divided into 8 blocks. Cache contains 4 blocks. We know: - A memory address has 4 bits. - The 4-bit memory address is divided into the fields below. 1 bit 2 bits 1 bit Tag Block Offset 4 bits 21 Oda images Shuttu Stoch, Ine. Copyright 2014 by Jones & Bartlett Learning, LC Ascend learning Company www.bing.com

6.4 Cache Memory EXAMPLE 6.2 Assume a byte-addressable memory consists of 214 bytes, cache has 16 blocks, and each block has 8 bytes. 214 211 - The number of memory blocks are: 23 - Each main memory address requires 14 bits. Of this 14-bit address field, the rightmost 3 bits reflect the offset field. We need 4 bits to select a specific block in cache, so the block field consists of the middle 4 bits. The remaining 7 bits make up the tag field. 7 bits 4 bits 3 bits Tag Block Offset 14 bits 20 Odun Images Shuttu Stoch, Ine Copyright 2014 by Jones & Barriert Laarning Centending Company www.bing.com