a 1 RF RF2 Wte Wto d Tg = 0 = (RF2)(1) – (Wto)(d) - (Wty)('/21) A 75 kg, 1.75 m tall person lays on a 3 kg, 2 m long boa

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answerhappygod
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a 1 RF RF2 Wte Wto d Tg = 0 = (RF2)(1) – (Wto)(d) - (Wty)('/21) A 75 kg, 1.75 m tall person lays on a 3 kg, 2 m long boa

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A 1 Rf Rf2 Wte Wto D Tg 0 Rf2 1 Wto D Wty 21 A 75 Kg 1 75 M Tall Person Lays On A 3 Kg 2 M Long Boa 1
A 1 Rf Rf2 Wte Wto D Tg 0 Rf2 1 Wto D Wty 21 A 75 Kg 1 75 M Tall Person Lays On A 3 Kg 2 M Long Boa 1 (35.2 KiB) Viewed 67 times
a 1 RF RF2 Wte Wto d Tg = 0 = (RF2)(1) – (Wto)(d) - (Wty)('/21) A 75 kg, 1.75 m tall person lays on a 3 kg, 2 m long board. The reaction force reading on the scale is 400 N. What is d, the distance from the axis of rotation to the person's center of mass? 2 m 1.75 m © 1.05 m 1.25 m
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