a 1 RF RF2 Wte Wto d Tg = 0 = (RF2)(1) – (Wto)(d) - (Wty)('/21) A 75 kg, 1.75 m tall person lays on a 3 kg, 2 m long boa

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

a 1 RF RF2 Wte Wto d Tg = 0 = (RF2)(1) – (Wto)(d) - (Wty)('/21) A 75 kg, 1.75 m tall person lays on a 3 kg, 2 m long boa

Post by answerhappygod »

A 1 Rf Rf2 Wte Wto D Tg 0 Rf2 1 Wto D Wty 21 A 75 Kg 1 75 M Tall Person Lays On A 3 Kg 2 M Long Boa 1
A 1 Rf Rf2 Wte Wto D Tg 0 Rf2 1 Wto D Wty 21 A 75 Kg 1 75 M Tall Person Lays On A 3 Kg 2 M Long Boa 1 (35.2 KiB) Viewed 66 times
a 1 RF RF2 Wte Wto d Tg = 0 = (RF2)(1) – (Wto)(d) - (Wty)('/21) A 75 kg, 1.75 m tall person lays on a 3 kg, 2 m long board. The reaction force reading on the scale is 400 N. What is d, the distance from the axis of rotation to the person's center of mass? 2 m 1.75 m © 1.05 m 1.25 m
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Top
Post Reply

Return to “Archived Questions & Answers”