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VCC 18V RC R1 270 C1 = 1 F Rs W 6000 C2 IH 2.2uF 01 2N2222A BDC - 220 RL. R2 Vs 100mVrms RE1 Bac +220 3.9ΚΩ 1kHz 0" RE2
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answerhappygod
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VCC 18V RC R1 270 C1 = 1 F Rs W 6000 C2 IH 2.2uF 01 2N2222A BDC - 220 RL. R2 Vs 100mVrms RE1 Bac +220 3.9ΚΩ 1kHz 0" RE2
VCC 18V RC R1 270 C1 = 1 F Rs W 6000 C2 IH 2.2uF 01 2N2222A BDC - 220 RL. R2 Vs 100mVrms RE1 Bac +220 3.9ΚΩ 1kHz 0" RE2 C3 =477F Calculate the value of the internal admittance of the BJT transistor in the circuit re = 110, given that ) = 4.76 MA Also NOTE Only place the value of the answer in the answer space do not put the SI Units in the answer space given. Answer:
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