- 1 (32.82 KiB) Viewed 21 times
VCC 18V RC R1 270 C1 = 1 F Rs W 6000 C2 IH 2.2uF 01 2N2222A BDC - 220 RL. R2 Vs 100mVrms RE1 Bac +220 3.9ΚΩ 1kHz 0" RE2
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
VCC 18V RC R1 270 C1 = 1 F Rs W 6000 C2 IH 2.2uF 01 2N2222A BDC - 220 RL. R2 Vs 100mVrms RE1 Bac +220 3.9ΚΩ 1kHz 0" RE2
VCC 18V RC R1 270 C1 = 1 F Rs W 6000 C2 IH 2.2uF 01 2N2222A BDC - 220 RL. R2 Vs 100mVrms RE1 Bac +220 3.9ΚΩ 1kHz 0" RE2 C3 =477F Calculate the value of the internal admittance of the BJT transistor in the circuit re = 110, given that ) = 4.76 MA Also NOTE Only place the value of the answer in the answer space do not put the SI Units in the answer space given. Answer:
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!