k= 2.000 N/m M=0.125kg man cocoooooo A 0.125kg mass is attached to a horizontal spring of spring constant k = 2 N/m and

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K 2 000 N M M 0 125kg Man Cocoooooo A 0 125kg Mass Is Attached To A Horizontal Spring Of Spring Constant K 2 N M And 1 (121.72 KiB) Viewed 40 times

k= 2.000 N/m M=0.125kg man cocoooooo A 0.125kg mass is attached to a horizontal spring of spring constant k = 2 N/m and set into Oscillation. Assume frictionless floor. What is the angular frequency o of the vibration? 0 = How about the vibrating frequency f in Hz? f = The position of the mass is given as x = A cos (ot + oo). With your calculated value of o, fill in the following table (don't forget to set your calculator to "radian mode"). Each row represents a different oscillation with the same spring, pay attention to sign: x (m) v (m/s) a (m/s) t(s) F(N) 2.5 A (m) 0.03 0.04 0.06 00 (rad) 0.3 0.2 0.4 0.02 0.04 0.1 0.3 -0.2 0 0 0.5 0.04 0.1 0.1 PART B Each of the rows in the following table represents an oscillation of a different spring and mass. Fill in the blanks. E is the total energy. Vmax, V, Xmax, and x are all positive in values. A (m) Xmax m (kg) k (N/m) 0 E() Vmax (m/s) (m/s) (rad/s) 5 xat t=0 (m) 0.01 v at t=0 (m/s) 0.05 20 9.0 1.0 0.3 0.5 2.0 0.15 5.0 2.0 5.0 ol 0.6 0.6 2.0 5.0 0.2 2.0 0.1