HW for sure, in detail, thanks
Q1
(a) According to the equation, P = Po * e^(-alpha*Y),
where Po is the atmosphere at sea level and Y is the height, 33
kPas happens at the top of mount everest. What is the constant
alpha in that equation?
(b) What would be the pressure in Pascals at 1 km,
using the equation and alpha constant found above.
30 25 20 Altitude (km) 15 Mount Everest 8.85 km (29,035 ft) 33 kPa (PO27.1 kPa) 10 Average sea-level pressure 101.3 kPa (PO, 21.3 kPa) 5 0 0 10 20 30 40 50 60 70 80 90 100 110 Atmospheric pressure (kPa)
HW for sure, in detail, thanks Q1 (a) According to the equation, P = Po * e^(-alpha*Y), where Po is the atmosphere at s
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HW for sure, in detail, thanks Q1 (a) According to the equation, P = Po * e^(-alpha*Y), where Po is the atmosphere at s
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