(1 point) In order to compare the means of two populations, independent random samples of 69 observations are selected f

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(1 point) In order to compare the means of two populations, independent random samples of 69 observations are selected f

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1 Point In Order To Compare The Means Of Two Populations Independent Random Samples Of 69 Observations Are Selected F 1
1 Point In Order To Compare The Means Of Two Populations Independent Random Samples Of 69 Observations Are Selected F 1 (138.7 KiB) Viewed 28 times
(1 point) In order to compare the means of two populations, independent random samples of 69 observations are selected from each population, with the following results: Sample 1 Sample 2 21 = 322 = 0 $1 = 130 82 = 175 (a) .Use a 99% confidence interval to estimate the difference between the population means (441 – M2) < (41 - M2) (b) Test the null hypothesis: H, : (41 - H2) = 0 versus the alternative hypothesis: H, : (M1 - M2) #0 Using a = 0.01, give the following: (i) the test statistic z= (ii) the positive critical score (iii) the negative critical score The final conclustion is O A. We can reject the null hypothesis that (11 – 12) = 0 and accept that (11 – 12) 701 OB. There is not sufficient evidence to reject the null hypothesis that (M1 - Mz) = 0. (c) . Test the null hypothesis: H : (ui – M2) = 22 versus the alternative hypothesis: H, : (M1 – M2) + 22 Using a = 0.011, give the following: (1) the test statistic z (ii), the positive critical score (iii) the negative critical 2 score The final conclustion is A. There is not sufficient evidence to reject the null hypothesis that (M1 – N2) = 22 OB. We can reject the null hypothesis that (ui – uz) = 22 and accept that (u1 - 2) + 22
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