2. In an insurance company the processing times for 80 claims are gathered. A T-test shall be used to check whether the average processing time is above 75 minutes (significance level 5%). One Sample t-test data: dauer t = 4.3553, df = 79, p-value = 1.975e-05 alternative hypothesis: true mean is greater than 75 95 percent confidence interval: 77.16246 sample estimates: mean of x 78.5 Inf a) Formulate null and alternative hypotheses using the notations of the lecture. b) Interpret the above R output. What do the respective numbers mean? c) Interpret the test and the test result in the context of the task. d) True or false?" Due to the test result, it is not possible to say that the average processing time is significantly greater than 75."
Example: sample size Let O be the percentage of Austrians in favor for reelections. Null hypothesis: Ho: 0 < 0o = 0.5 Alternative: Ha: 0 > 0o = 0.5 The original survey: fn-00 0.5420168-0.5 1.296 20(1-02 0.5.1-0.5) T= 238 New survey with n such that T is significant: 0.5420168 - 0.5 T= >1.64 0.5.(1-0.5) n n> 1.642.0.5. (1 -0.5) = 380.874 – 381 (rounding up!) (0.5420168 – 0.5)2 At least 381 persons would have had to be interviewed.
2. In an insurance company the processing times for 80 claims are gathered. A T-test shall be used to check whether the
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2. In an insurance company the processing times for 80 claims are gathered. A T-test shall be used to check whether the
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