- The Data For Airfreight Breakage Csv Is As Follows Broken Transfer S 16 1 9 0 17 2 12 0 22 3 13 1 Co 0 15 1 19 2 11 1 (31.16 KiB) Viewed 40 times
# The data for airfreight_breakage.csv is as follows: #broken #transfer S 16 1 9 0 17 2 12 0 22 3 13 1 co 0 15 1 19 2 11
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answerhappygod
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# The data for airfreight_breakage.csv is as follows: #broken #transfer S 16 1 9 0 17 2 12 0 22 3 13 1 co 0 15 1 19 2 11
# The data for airfreight_breakage.csv is as follows: #broken #transfer S 16 1 9 0 17 2 12 0 22 3 13 1 co 0 15 1 19 2 11 0 #We have fitted a linear regression model: x=airfreight_breakage #transfers y=airfreight_breakage #broken fit = Im[y-x) # We found the intercept confidence interval: confint (fit,level=97.5) #We get (8.670370, 11.729630) A consultant has suggested, on the basis of previous experience, that the mean number of broken ampules should not exceed 9.0 when no transfers are made. Conduct an appropriate test, using alpha = .025. State the hypothesis, decision rule, and conclusion. What is the p-value of the test?
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