Find the equation of the tangent line to the curve y = [9x + 118* [sin(8x) + 1]** at (0,1) using logarithmic differentia

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Find The Equation Of The Tangent Line To The Curve Y 9x 118 Sin 8x 1 At 0 1 Using Logarithmic Differentia 1 (34.88 KiB) Viewed 26 times

Find the equation of the tangent line to the curve y = [9x + 118* [sin(8x) + 1]** at (0,1) using logarithmic differentiation and the following steps. (a) Find In(y). In(y) = 8x +9x In(y) = = 8x: +9x (b) Find y y ✓ v = () (c) Find the slope of the tangent line at x = 0. m= (d) Find the tangent line to the curve at (0,1). y = A correct answer is In(9.x + 1), which can be typed in as follows: log(9*x+2) A correct answer is In(sin(8 - x) + 1), which can be typed in as follows: logsin(8-x)+1) A correct answer is 9 . In(sin(8 - x) + 1) + 8 . In(9-x+1)+ 72.X-COX2 +77.xwhich can be typed in as follows: 9xtog(sin(84x)+1)+8xlog (9*x+1)+(72ex+cos (8 x)/(sin(8**)+1) +72*x)/(2*x+1) A correct answer is 0, which can be typed in as follows: A correct answer is 1, which can be typed in as follows: 1 Nin(8-x)+1 +1