- F 0 25 M C2 15n S M He Q4 A Massless Bar Of Length 1 M Is Pivoted At One End And Subjected To A Force F At The Other 1 (53.13 KiB) Viewed 43 times
F 0.25 m C2 = 15N-s/m HE Q4. A massless bar of length 1 m is pivoted at one end and subjected to a force F at the other
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F 0.25 m C2 = 15N-s/m HE Q4. A massless bar of length 1 m is pivoted at one end and subjected to a force F at the other
F 0.25 m C2 = 15N-s/m HE Q4. A massless bar of length 1 m is pivoted at one end and subjected to a force F at the other end. Two translational dampers, with damping constants ci=10 N-s/m and c2 = 15 N-s/m are connected to the bar as shown in the Figure. Find the equivalent damping constant Ceq, of the system so that the force F at point A can be expressed as F = Ceq V, where v is the linear velocity of point A. 0.75 m =10N-s/m 0.25 m
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