Photos - Q3 ans 1.PNG Photos - Q3 ans 2.PNG - Cnr E + 71 + Q 目 而 ♡ 女 Off Document1 - Word Rafal Skaskiewicz RS 6 1 0 Lix

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Photos - Q3 ans 1.PNG Photos - Q3 ans 2.PNG - Cnr E + 71 + Q 目 而 ♡ 女 Off Document1 - Word Rafal Skaskiewicz RS 6 1 0 Lix Tus me Insert Draw Design Layout References Mailings Review View Help LOQd 1 --> 0kw@cos4 = 1 A Ą O Loov, 50H2 IN Rate ans Paste Font Paragraph Styles Editing Dictate Sensitivity Editor Reuse N Files Power Ipnose √3 Ve ? Cobo load 3 -> 5kw @coso 1 ipboard Styles Voice Sensitivity Editor Reuse Files Lab fog Line 0:- IL Load 2-8kW CCBQ=1 L34 x 400 x TLXL 10x10² 。 10x109, I received two different calculations for this question, could you please see both answers and give me a final and correct solution. | TL 14.43 amp V = hoov (line to line voltage) 400x Four Line @: Vpha 400 Question 3. below shows a 3 phase 400V 50Hz 4-wire system with the following inductive loads connected between Line and Neutral: P √3 xVL XI 22* Cogd - 8x103 Vox 4000 TL * 1) line currents, Ila a Vph power of Load 1 Load 1 - 10KW @ unity power factor Load 2 -8KW @unity power factor Load 3 - 5KW @ unity power factor Loo V3 X 10X103 -0.023 8x103 TL₂ = 11.54 omp 2 x 400X I 2 2 = 0.023 10 A four Line Calculate: (i) the current in each line. (ii) the current in the neutral. 3 VL P Vph = 0.029 IL2= 7.2 Amp hoo V8x8x103 power of Loada ng cost 3x103 400x IX V2 7.2.17 amp ILZ LI (I L2 = 0.029 Lon hoo Load 1 Itza o ohon 400 V 50 Hz in Neurocal Vph power of 200d 3 VOX SX 103 Load 3 Total current I Lot Il2 + ILG (14.43+ 11.547+ 72.17) IN= (11: Doubleal Load 2 Figure 26 66 (AN 22 words m 98.147 Focus English (Ireland) 1 IN 100% 2) At neutral point, Ilit Il2 + IL 3 = IN IN=0.023 +0.029 to one In = 0.098A b MERA B0422 orton