dL** dt* dPC* -k14 dC* + dt*2 koff dt* -k14 dC* k12 ( 1C* koff dt* dt* k14.0* = + ) tu koff koff Figure 3. Dynamic respo

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answerhappygod
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dL** dt* dPC* -k14 dC* + dt*2 koff dt* -k14 dC* k12 ( 1C* koff dt* dt* k14.0* = + ) tu koff koff Figure 3. Dynamic respo

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Dl Dt Dpc K14 Dc Dt 2 Koff Dt K14 Dc K12 1c Koff Dt Dt K14 0 Tu Koff Koff Figure 3 Dynamic Respo 1
Dl Dt Dpc K14 Dc Dt 2 Koff Dt K14 Dc K12 1c Koff Dt Dt K14 0 Tu Koff Koff Figure 3 Dynamic Respo 1 (338.23 KiB) Viewed 18 times
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dL** dt* dPC* -k14 dC* + dt*2 koff dt* -k14 dC* k12 ( 1C* koff dt* dt* k14.0* = + ) tu koff koff Figure 3. Dynamic response of the ligand/receptor where **, * show normalisation and can be omitted when solving the tasks. Laplace transform and transfer function (5 pts) (a) Simplify and find the Laplace transform of the equation Figure 3. (b) Apply zero initial conditions to (a) and solve the transfer function for the number of ligand- receptor complex molecules over u. The values of the constants in the equation above (Figure 3) are provided here: k12 = 4.9 (1/min), k14 = 4.5 (1/min), koff = 0.7x60 (1/min)
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