FIRST 4 PARTS ARE DONE. ATTEMPT PART (E) ONLY. FIRST 4 PARTS ARE DONE. ATTEMPT PART (E) ONLY.

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answerhappygod
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FIRST 4 PARTS ARE DONE. ATTEMPT PART (E) ONLY. FIRST 4 PARTS ARE DONE. ATTEMPT PART (E) ONLY.

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FIRST 4 PARTS ARE DONE. ATTEMPT PART (E)
ONLY.
First 4 Parts Are Done Attempt Part E Only First 4 Parts Are Done Attempt Part E Only 1
First 4 Parts Are Done Attempt Part E Only First 4 Parts Are Done Attempt Part E Only 1 (64.67 KiB) Viewed 23 times
FIRST 4 PARTS ARE DONE. ATTEMPT PART (E)
ONLY.
= An discrete time LTI system is characterized by the following LCCDE: y[n] = -0.5y[n – 1] + x[n] – 0.9x[n – 1] a. Find system frequency response H(w) b. Find system impulse response h[n] c. Find the system output for an input x[n] = cos(0.5an + 0.5). d. Find the system output for an input x(t) = ej0.47n. 1 e. Find the system output for an input whose X(w) = S(W) + 1+jw = =
Jake (حم) X b) Howl e ja 1 fake enverse . Greven difference Equation yeni=-0.59(n-1 trin)-oegelung fourier transform Y(n+oosyon-1) = x() -0.97(n-1) Y(w) +ousē ay ico) = x(w)-o.ge fra HIO) Ž Y1W) = 11-ooge sw hoose to oog 1-toos) e so 7-(-oos ējw) henda goosruins or com ajuns at (n-1) transform üln) - ) =(-0.5) on hin) = fo-sja üln) - 0.9 Goos) Mü'n-1) geuren min) scoscoos n nto's) Yo-o-SIT _jOSIT H (Wol=10ogejwo 1-0 ye toos esco - loog (-)) =l+joog ito.s(-i) I-jous 1:203 (68.55" <H1 Wol=68055240196 Systemy output yen) =) Hewas) costoistin + O'I +CH) = 1.203 cos (oorsien +005 +1-196 yens = 1,203 coscosan+2.7) alte ejourin c) - To.sk to.5 H1-203 d) iG ywoo 0.YIT I-Ooge72 /0۰۹ م 009 -ا = ( ههه ) H toos2-78, 0.896 <1-26rd Itoos ojo.45 0.896(72•249 y (n) = Hlwoll ouran (741210 ) yen) = 0,896 e jco.unnt 1026)
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