- 00 The Block Diagram Shown Below Implements A Continuous Time System Where A A B B And B Are Constants And X T A 1 (110.99 KiB) Viewed 26 times
- 00 The Block Diagram Shown Below Implements A Continuous Time System Where A A B B And B Are Constants And X T A 2 (8.48 KiB) Viewed 26 times
- 00 The Block Diagram Shown Below Implements A Continuous Time System Where A A B B And B Are Constants And X T A 3 (40.69 KiB) Viewed 26 times
-00 The block diagram shown below implements a continuous time system where a, a, b, b, and b, are constants, and x(t) and y(t) are respectively the input and the output of the system. The integrators are implemented using the op-amp circuit shown below. Simple circuit analysis assuming an ideal op-amp can demonstrate that the relationship between the voltage v (t) and the 1 voltage vo(t) is volt) j v,(re)de. Therefore, analysis of the block diagram requires that . the polarity inversion and the scaling factor 1/RC be included in the equations. Therefore, the relationship in the diagram between f(t) and f(t) must be written as fly(t) = -ky | f(t)dt where ky =1/RC. In most integration circuits, the integration constant k, can be varied. This can be done if the circuit has a potentiometer where the resistance value can be varied or a set of capacitors can be switched on individually or in groups. -30 bi f(t) b2 x(t) Σ In the TIMS/EMONA + y(t) equipment, the value of resistance is R=10 KN S and C = 180 pF (fixed) and two additional -01 values C = 2 nF and Σ Σ C = 4 nF and be f(1)(t) individually switched on or off. Each Laplace TIMS EMONA module has one integrator and two three-input adders in addition to the f(2)(t) integrator) where in front of each input the is a scalar multiplier that can be adjusted in amplitude (from a value of 0 to a value of 2) and adjusted in polarity (+ or -). (See separate document showing the principal details of this module.) -do bo
ic IR R O + a + Vi Ve 16
نی - 2 In this part, a second order high pass filter is implemented by adjusting the parameters in the system above. The transfer function of such a filter is H(s) = K where H(O)= K and s? +20,5 +0. o is the filter cutoff frequency. Assume for convenience that K =1, and determine analytically the step response r(t) of the system without assigning a value to m. Use MATLAB to plot r(t) specifically for 0. = 275000 rps. Also use MATLAB to plot for the given value of the magnitude H(jo) of the transfer function as well as the phase ZH(jo) of the transfer function. Show that H(jo.)=j. =