S 3 TIMES (days) MOST LIKELY Activity PESSIMISTIC OPTIMISTIC Start Node Finish Node to tm Lp 62 1 A 2 26 35 26 35 B 1 3 23 С 2 60 S 12 24 57 D 45 3 4 33 E 21 33 4 5 9 Given the Activity on Arrow Diagram and the data found in the table above, calculate each of the following v.
Activity A.........te = 38 Standard Deviation = 6 Activity B. Standard Deviation = AJ Activity C......... Standard Deviation = Activity D.........te A/ Standard Deviation = Activity E......... Standard Deviation 4 Path 1-2-5 A/ Mean Time Standard Deviation - 10
Path 1-3-4-5 Mean Time = A Standard Deviation = A
S 3 TIMES (days) MOST LIKELY Activity PESSIMISTIC OPTIMISTIC Start Node Finish Node to tm Lp 62 1 A 2 26 35 26 35 B 1 3
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
S 3 TIMES (days) MOST LIKELY Activity PESSIMISTIC OPTIMISTIC Start Node Finish Node to tm Lp 62 1 A 2 26 35 26 35 B 1 3
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!