Marks Consider the following reaction: 10 KNO3(s) + 8 C(s) + 3 S(s) → 2 K2CO3(s) + 3 K, SO4(s) + 6 CO2(g) + 5 Nalg) + If you mix 1.00 kg of KNO3 with 1.00 kg of sulfur in the presence of excess carbon and the reaction proceeds with 85% yield, what mass of solid products (i.e., K2CO3 plus K2SO4) will you make? O a. 2.00 kg O b. 672 g Oc. 1.26 kg O d. 1.05 kg O e. 791 g
Moks The ionic radius of the Na* cation is much different than that of the K* cation. Choose the one answer that properly identifies their size difference and justifies its fundamental cause. a. Both are in the same period, but sodium cation has fewer energy levels with filled orbitals. That means the outermost electrons of this ion will be farther from its nucleus, so it has the smaller radius. Ob. Both are in the same group, but the potassium cation has a lower nuclear effective charge. That means the electrons of this ion are more strongly attracted to its nucleus, hence the electronic cloud is more compressed, which results in a smaller size. O c. Both are in the same group, but potassium cation has more protons. That means its electrons are pulled with greater strength towards the nucleus, so it has the smaller radius. d. Both are in the same group, but the potassium cation has more core shells with filled orbitals. That means some of the electrons of this ion are more distant fom the nucleus, which results in a bigge radius. 2. Both are in the same group, but potassium cation has more energy levels with filled orbitals. Tha means some of the electrons of this ion are more distant from the nucleus, so this ion has a sm radius.
Marks Consider the following reaction: 10 KNO3(s) + 8 C(s) + 3 S(s) → 2 K2CO3(s) + 3 K, SO4(s) + 6 CO2(g) + 5 Nalg) + If
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Marks Consider the following reaction: 10 KNO3(s) + 8 C(s) + 3 S(s) → 2 K2CO3(s) + 3 K, SO4(s) + 6 CO2(g) + 5 Nalg) + If
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