A leak occurs in a chemical reactor with an equimolar mixture of O. CH. CH. CO, CO, gases. After a few minutes, a co det

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A leak occurs in a chemical reactor with an equimolar mixture of O. CH. CH. CO, CO, gases. After a few minutes, a co det

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A Leak Occurs In A Chemical Reactor With An Equimolar Mixture Of O Ch Ch Co Co Gases After A Few Minutes A Co Det 1
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A leak occurs in a chemical reactor with an equimolar mixture of O. CH. CH. CO, CO, gases. After a few minutes, a co detector located on the other side of that room, triggers an alarm. At that exact moment, select among the following sentences, THE ONE THAT APPLIES. a The concentration of CO2 is higher than that of the other gases because it is the heaviest molecule. Ob. The fraction of all these 5 gases left inside the container after the leak will remain equimolar. Methane was detected first because its lower molar mass makes its average kinetic energy lower. O d. The CO was the first gas that made it to the detector because it is the lightest of them all. Oc Oe. Among the gases left inside the container, CHA will be the one in smaller proportion
The sequence of reactions shown in the box is used for the preparation of silicon, which is later purified for electronic applications. Which one choice CORRECTLY describes one of the reactions? i. SiO2(S) + 2 C(s) + Si(s)+2 CO(g) ii. Si(s) + 3 HCl(g) - SiHCl3(g) + H2(g) iii. SiHCl3(g) + H2(g) → Si(s) + 3 HCl(g) O a. Si is oxidized in reaction (i). O b. Cl is reduced in reaction (iii). O c. Some H is reduced in reaction (iii). O d. Si is oxidized in reaction (ii). O e. Some H is oxidized in reaction (ii).
Manganese is a transition metal in the fourth row of the periodic table. In its compounds, +ll and +IV are the most common oxidation states. Select the electronic configuration that best represents the smallest Mn cation. O a. [Ar] 482 303 O b. [Ar]3d3 O c. [Ar] 4s2 3d5 O d. [Ar] 482 3d O e. [Ar] 4s2 3d? Of O f. [Ar] 4s2 3d" Oе O g. [Ar] 3d5
Pick the correct representation of the valence shell for the element with Z = 25. O a ns (n-1)d O b. ns (n-1)d O c. ns (n-1)d O d. ns (n-1)d Oe. ns (n-1)d Of.
ns (n-1)d O c. ns (n-1)d O d. ns (n-1)d O e. ns (n-1)d Of. TI (n-1)d ns O g. ns (n-1)d
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