A room of 5.0 x 4.0 x 3.0 m is shown in Figure Q6-1. The front envelope is a glass curtain wall. A floor heating panel o

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A Room Of 5 0 X 4 0 X 3 0 M Is Shown In Figure Q6 1 The Front Envelope Is A Glass Curtain Wall A Floor Heating Panel O 1 (74.26 KiB) Viewed 22 times

A Room Of 5 0 X 4 0 X 3 0 M Is Shown In Figure Q6 1 The Front Envelope Is A Glass Curtain Wall A Floor Heating Panel O 2 (63.88 KiB) Viewed 22 times

A room of 5.0 x 4.0 x 3.0 m is shown in Figure Q6-1. The front envelope is a glass curtain wall. A floor heating panel of 5.0 x 3.0 m is installed to heat the room as shown in the figure. The temperature on the interior surface of the curtain wall is 15 °C, the temperature on the interior surface of the heating panel is 28 °C, and the temperature on the remaining interior surfaces of the room is 20 °C. (a) Determine the view factor from the curtain wall to the floor surface (Few-), the view factor from the curtain wall to the remaining surfaces excluding the floor surface (Few-rs), and the view factor from the curtain wall to the heating panel surface (Few.hp). (12 marks) (b) Show the thermal circuit representing all the radiant heat transfer processes among the room interior surfaces, assuming all the interior surfaces are grey body. (Be sure to label all elements and nodes in symbolic form and to give the expressions of all the resistances between nodes). (6 marks) (c) Calculate the radiation heat transfer rate from the heating panel to the curtain wall surface. The values of emissivity of both surfaces are 0.92. The Stefan-Boltzmann constant = 5.67 x 10-8 W/m². K+ (7 marks) 4.0 m Glass curtain wall Heating panel 3.0 m 3.0 m 5.0 m Figure Q6-1. Sketch of a room (Note that Figures Q6-2 and Q6-3 are provided in the Appendixes at the end of the question paper for determining view factors for parallel and perpendicular rectangles.)
Appendix: Figures for determining view factors. 1.0 0.8 XD 0.6 0.41 D 0 0.2 0.1 0.08 0.06 0.04 Zerurat TELEN 0.02 0.01 0.1 0.2 0.4 0.6 0.81 ID 4 6 8 10 Figure Q6-2 View factor for directly opposed rectangles 0.50 Y = 0.1 Dimension ratio, Y 0.11 0.40 10.2 0.3 0.30 0.64 Shape factor F- 0.8 1,0 0.20 A, - Area on which heat transfer equation is based. Y = yix Z - 2x 1.5 0.10 10-4 73.0 GO 16.0 Asymptotes 8.0 1.0 Scale changes here- 2.0 3.0 4.06 8 10 Dimension ratio, Z Figure Q6-3 View factor for adjacent rectangles in perpendicular planes