Two loudspeakers are mounted on a wall, one h. 264 m above the other. Exactly 8.00 meters to the right of the midpoint o

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Two Loudspeakers Are Mounted On A Wall One H 264 M Above The Other Exactly 8 00 Meters To The Right Of The Midpoint O 1 (27.18 KiB) Viewed 38 times

Two loudspeakers are mounted on a wall, one h. 264 m above the other. Exactly 8.00 meters to the right of the midpoint o microphone rests at point o Point Ois equally distant from each loudspeaker The loudspeakers are driven by the same tone generator and vibrate in phase at 370 Ha. It is possible to create a condition of destructive interference at Point O by changing one or both of the path lengths (', and r) between speaker and microphone Suppose that this is done by raising the upper speaker while leaving the lower speaker in place. What is the smallest vertical distance in m) that you would need to raise the upper speaker by. In order to create destructive interference at Point Of (The speed of sound waves in air is 343 m/s.) 1408 X Raising the upper speaker, while leaving the lower speaker in place, will increase their vertical separation as well as the upper path length (r). First calculate the wavelength of the sound, I. In terms off, how much does needs to increase in order to change the interference at Point Ofrom constructive to destructive? Calculate the new r, Walue (in meters). Then use peometry and the Pythagorean theorem to work out the quantityAy, from which you can obtain ar uning simple acthmetic, . m