41-2 14.811 + PU 412 457 18 19.11 t=4.11 2) A car traveling 20m/s accelerates to 35m/s. During this acceleration, the car traveled 290 meters. What is the car's acceleration? 1900 290 - 15 15 15 t= 19.3 m/s
1) An object is dropped off a 41m tall building. How long will it take for the object to reach the ground? AY= 1 gt² + Vot 41 = 2 (9.81)+2 to 41-457? +=H.M A car traveling 20m/s accelerates to 35m/s. During this acceleration, the car tra meters. What is the car's acceleration? Roms 290=
41-2 14.811 + PU 412 457 18 19.11 t=4.11 2) A car traveling 20m/s accelerates to 35m/s. During this acceleration, the ca
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41-2 14.811 + PU 412 457 18 19.11 t=4.11 2) A car traveling 20m/s accelerates to 35m/s. During this acceleration, the ca
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