O Solutions Submitted Max 2 A Weight Wis Supported By Two Cables Anchored A Distance Lac Apart The Cable Length Lan 1 (321.33 KiB) Viewed 36 times
O Solutions Submitted Max 2 A Weight Wis Supported By Two Cables Anchored A Distance Lac Apart The Cable Length Lan 2 (246.79 KiB) Viewed 36 times
O solutions submitted (max: 2) A weight Wis supported by two cables anchored a distance Lac apart. The cable length LAN is given, but the length Lac is to be selected. For the weight to remain stationary, the total horizontal force and total vertical force must each be zero. This principle (which you will learn in Statics) gives the equations: -TACOS 0 + Tac cos=0 Tassin + Toc sino - W If LAC = 61, LAN = 31. and W = 2500lb, write a program to . T_AB for the tension on L 1. Compute the tension in the two cables (T. and T ) for 0 5 .10...90' (use variable theta for 8 phi for T_BC for the tension on Lac) 2. Generate a plot for Tan vs. 8 and Tac VS. (both on the same graph) Note: Do not treat triangle ABC as a right triangle A hint about how to approach using triangle ABC is available here
C Reset D MATLAB Documentation 1 Enter the given information 6 create angles for theta in radius 9 find other angle (via trigonometry) 13 % find other length by law of sines silve for the forces generate the plot, add labels and title D SolpracExam1.pdf
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