Coulomb's law for the magnitude of the force FF between two particles with charges QQ and Q′Q′ separated by a distance d

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Coulomb's law for the magnitude of theforce FF between two particles withcharges QQ and Q′Q′ separated by adistance dd is
|F|=K|QQ′|d2|F|=K|QQ′|d2,
where K=14πϵ0K=14πϵ0,and ϵ0=8.854×10−12C2/(N⋅m2)ϵ0=8.854×10−12C2/(N⋅m2) is thepermittivity of free space.
Consider two point charges located onthe x axis: one charge, q1q1 =-10.5 nCnC , is located at x1x1 =-1.710 mm ; the second charge, q2q2 =35.5 nCnC , is at theorigin (x=0.0000)(x=0.0000).
Part A
What is the net force exerted by these two charges on a thirdcharge q3q3 = 45.5 nCnC placedbetween q1q1 and q2q2 at x3x3 =-1.080 mm ?
Your answer may be positive or negative, depending on thedirection of the force.
Express your answer numerically in newtons to three significantfigures.