Next: Move forward by clicking NEXT for 6 tim san from the main page of Electrostatics visualization BAT for 6 times or

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Next Move Forward By Clicking Next For 6 Tim San From The Main Page Of Electrostatics Visualization Bat For 6 Times Or 1 (545.05 KiB) Viewed 44 times

Next: Move forward by clicking NEXT for 6 tim san from the main page of Electrostatics visualization BAT for 6 times or directly im to Renulsion of charges with same It the instructor read the description of "Repulsion of charges with same Sign to me the movie and answer the following questions: of Repulsion of charges with same sign to the class. Observe Will the field lines ever cross? (Yes or No) Why? h These two positive charges have same magnitude. Is there any location, where the E field is zero? If yes, where? 5. Go back to "Integrating along a Line of charge". Let the instructor read the entire description. a. First, the observer is just above the middle point of the finite charged line. Notice the directions and lengths of many small arrows representine the small E fields de created by each piece of small segment of charge dq. Notice the accumulated effect of many small dE (shown as a bie-head arrow E), which is a vector sum" of all the small de created by the small segments of charges highlighted in yellow. The vector sum is not trivial. Is the total E field magnitude at that point _ _(equal to, smaller than, or bigger than the simple scalor sum of the all the dE magnitude? (Hint: Is the length of the big-head arrow (equal to, shorter than, or longer than the sum of the length for all the small dE arrows. Do these de vectors partially cancel out or add 100% as if they are in the same direction?) Due to symmetry, the direction of the total E field is _(Upward, up-left, or up-right), when the observer is just above the middle point of the charged line? b. Next, we move the observer rightward horizontally, the direction of the total E field is (Upward, up-left, up-right, leftward, or rightward), when the observer is above and to the right respecting to the middle point of the charged line. c. Next, move the observer to a location along the line of the charged rod (on the right side of the rod). The direction of the total E field at that location is now (Upward, up-left, or up-right, leftward, or rightward). At this location, is the total E field magnitude (equal to smaller than or bigger than the simple sum of the all the de magnitude? (Hint: Are these de vectors in the same direction for this case?) Note that when all the dE arrows are in the same direction, you can convert your vector integral (vector sum) into a simple scalar integral (a simple scalar sum). Otherwise, you will have to decompose vectors using trigonometry before summing or integrating dE.