Table E-1. Solution volumes for Groups 1 to 4. \begin{tabular}{ccccc} Stock Conc'n & 1.00mMI2 & 0.500MHCl & 1.60M aceto
Posted: Fri Jul 15, 2022 5:00 pm
Table E-1. Solution volumes for Groups 1 to 4. \begin{tabular}{ccccc} Stock Conc'n & 1.00mMI2 & 0.500MHCl & 1.60M acetone & water \& starch \\ Group & Volume, mL & Volume, mL & Volume, mL & Volume, mL \\ 1 & 10.00 & 25.00 & 25.00 & 10.0 \\ 2 & 5.00 & 25.00 & 25.00 & 15.0 \\ 3 & 10.00 & 25.00 & 15.00 & 20.0 \\ 4 & 10.00 & 15.00 & 25.00 & 20.0 \\ \hline \end{tabular}
Rate 3 Rate 1= ln([ acet 1/ acet 3)ln( Rate 1/ Rate 2)= n= R1e4 Rate 1=lnR1Rate= ln([HCl]⋅[HCl)6)ln( Rate 1/ Rate 6)= p= Write the rate law: Rate = Common Temperature Rate Constant Group 1 Group 2 Group 3 Group 4
Rate 3 Rate 1= ln([ acet 1/ acet 3)ln( Rate 1/ Rate 2)= n= R1e4 Rate 1=lnR1Rate= ln([HCl]⋅[HCl)6)ln( Rate 1/ Rate 6)= p= Write the rate law: Rate = Common Temperature Rate Constant Group 1 Group 2 Group 3 Group 4