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answerhappygod
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- Table E 1 Solution Volumes For Groups 1 To 4 Begin Tabular Ccccc Stock Conc N 1 00mmi2 0 500mhcl 1 60m Aceto 1 (14.47 KiB) Viewed 44 times
- Table E 1 Solution Volumes For Groups 1 To 4 Begin Tabular Ccccc Stock Conc N 1 00mmi2 0 500mhcl 1 60m Aceto 2 (34.84 KiB) Viewed 44 times
Table E-1. Solution volumes for Groups 1 to 4. \begin{tabular}{ccccc} Stock Conc'n & 1.00mMI2 & 0.500MHCl & 1.60M acetone & water \& starch \\ Group & Volume, mL & Volume, mL & Volume, mL & Volume, mL \\ 1 & 10.00 & 25.00 & 25.00 & 10.0 \\ 2 & 5.00 & 25.00 & 25.00 & 15.0 \\ 3 & 10.00 & 25.00 & 15.00 & 20.0 \\ 4 & 10.00 & 15.00 & 25.00 & 20.0 \\ \hline \end{tabular}
Rate 3 Rate 1= ln([ acet 1/ acet 3)ln( Rate 1/ Rate 2)= n= R1e4 Rate 1=lnR1Rate= ln([HCl]⋅[HCl)6)ln( Rate 1/ Rate 6)= p= Write the rate law: Rate = Common Temperature Rate Constant Group 1 Group 2 Group 3 Group 4
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