- 4 A 100 0 Ml Sample Of 0 18mhi Is Titrated With 0 27mkoh Determine The Ph Of The Solution After The Addition Of 110 0 1 (29.08 KiB) Viewed 34 times
4. A 100.0 mL sample of 0.18MHI is titrated with 0.27MKOH. Determine the pH of the solution after the addition of 110.0
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4. A 100.0 mL sample of 0.18MHI is titrated with 0.27MKOH. Determine the pH of the solution after the addition of 110.0
4. A 100.0 mL sample of 0.18MHI is titrated with 0.27MKOH. Determine the pH of the solution after the addition of 110.0 mL of KOH. V of HCN=100=0.1 L Molarity = Volime (L) moles Mo I of HCN=0.18M moles : Molanty ×M(L) MoI of COH=0.27M Moles of HEN=θ.18×θ.1 L=θ.018moles V of KOH added =110 mL Moles of KOH=θ.27×θ.11θ=θ.9297moles Moles of HCN = moles of KOH KOH→K++OH−HCN→H++CN−
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