Page 1 of 1

Consider a situation of simple harmonic motion in which the distance between the endpoints is 2.31 m and exactly 9 cycle

Posted: Fri Jul 15, 2022 7:26 am
by answerhappygod
Consider A Situation Of Simple Harmonic Motion In Which The Distance Between The Endpoints Is 2 31 M And Exactly 9 Cycle 1
Consider A Situation Of Simple Harmonic Motion In Which The Distance Between The Endpoints Is 2 31 M And Exactly 9 Cycle 1 (42.8 KiB) Viewed 44 times
Consider a situation of simple harmonic motion in which the distance between the endpoints is 2.31 m and exactly 9 cycles are completed in 22.6 s. When this motion is viewed as a projection of circular motion, what is the radius, r, and angular velocity, ω, of the circular motion? r= mω= rad/s