Consider a situation of simple harmonic motion in which the distance between the endpoints is 2.31 m and exactly 9 cycle

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Consider a situation of simple harmonic motion in which the distance between the endpoints is 2.31 m and exactly 9 cycle

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Consider A Situation Of Simple Harmonic Motion In Which The Distance Between The Endpoints Is 2 31 M And Exactly 9 Cycle 1
Consider A Situation Of Simple Harmonic Motion In Which The Distance Between The Endpoints Is 2 31 M And Exactly 9 Cycle 1 (42.8 KiB) Viewed 43 times
Consider a situation of simple harmonic motion in which the distance between the endpoints is 2.31 m and exactly 9 cycles are completed in 22.6 s. When this motion is viewed as a projection of circular motion, what is the radius, r, and angular velocity, ω, of the circular motion? r= mω= rad/s
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