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answerhappygod
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Circle your answer.
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For every integer n≥0,2n<(n+2)!. Proof (by mathematical induction): Let P(n) be the inequality 2n<(n+2)!. We will show that P(n) is true for every integer n≥0. Show that P(0) is true: Before simplifying, the left-hand side of P(0) is and the right-hand side is ห. The fact that the statement is true can be deduced from that fact that 20=1. [This is P(k), the inductive hypothesis.] We must show that P(k+1) is true. P(k+1) is the inequality Information about P(k+1) can be deduced from the following steps. Identify the reason for each step.
For every integer n≥0,2n<(n+2)!. Proof (by mathematical induction): Let P(n) be the inequality 2n<(n+2)!. We will show that P(n) is true for every integer n≥0. Show that P(0) is true: Before simplifying, the left-hand side of P(0) is and the right-hand side is ห. The fact that the statement is true can be deduced from that fact that 20=1. [This is P(k), the inductive hypothesis.] We must show that P(k+1) is true. P(k+1) is the inequality Information about P(k+1) can be deduced from the following steps. Identify the reason for each step.
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