Explain why the function is differentiable at the given point. f(x,y)=x6ey,(1,0) The partial derivatives are fx(x,y)= a
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Explain why the function is differentiable at the given point. f(x,y)=x6ey,(1,0) The partial derivatives are fx(x,y)= a
Explain why the function is differentiable at the given point. f(x,y)=x6ey,(1,0) The partial derivatives are fx(x,y)= and fy(x,y)= , so fx(1,0)= and fy(1,0)= . Both fx and fy are continuous functions, so f is differentiable at (1,0) Find the linearization L(x,y) of the function at (1,0). L(x,y)=
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