Explain why the function is differentiable at the given point. f(x,y)=x6ey,(1,0) The partial derivatives are fx​(x,y)= a

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Explain why the function is differentiable at the given point. f(x,y)=x6ey,(1,0) The partial derivatives are fx​(x,y)= a

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Explain Why The Function Is Differentiable At The Given Point F X Y X6ey 1 0 The Partial Derivatives Are Fx X Y A 1
Explain Why The Function Is Differentiable At The Given Point F X Y X6ey 1 0 The Partial Derivatives Are Fx X Y A 1 (49.73 KiB) Viewed 38 times
Explain why the function is differentiable at the given point. f(x,y)=x6ey,(1,0) The partial derivatives are fx​(x,y)= and fy​(x,y)= , so fx​(1,0)= and fy​(1,0)= . Both fx​ and fy​ are continuous functions, so f is differentiable at (1,0) Find the linearization L(x,y) of the function at (1,0). L(x,y)=
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