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Recall that dpd​[ln(ρ)]=p1​,p>0. Applying this rule as well as other rules of differentiation gives the following result

Posted: Thu Jul 14, 2022 4:36 pm
by answerhappygod
 1
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Recall that dpd​[ln(ρ)]=p1​,p>0. Applying this rule as well as other rules of differentiation gives the following result. T(p)T′(ρ)​=87.97+34.96ln(p)+7.91p​=p34.96​+27.91​pˉ​p34.96​+2p​7.91​​ Step 2 We have determined that the rate of change of temperature is given by the following. T′(p)=ρ34.96​+2ρ​7.91​ gives the following result. T′(ρ)=ρ34.96​+2ρ​7.91​ T′(65)=34.96++265​7.91​