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Recall that dpd[ln(ρ)]=p1,p>0. Applying this rule as well as other rules of differentiation gives the following result
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Recall that dpd[ln(ρ)]=p1,p>0. Applying this rule as well as other rules of differentiation gives the following result
Recall that dpd[ln(ρ)]=p1,p>0. Applying this rule as well as other rules of differentiation gives the following result. T(p)T′(ρ)=87.97+34.96ln(p)+7.91p=p34.96+27.91pˉp34.96+2p7.91 Step 2 We have determined that the rate of change of temperature is given by the following. T′(p)=ρ34.96+2ρ7.91 gives the following result. T′(ρ)=ρ34.96+2ρ7.91 T′(65)=34.96++2657.91
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