- F X 2 X X 2 2 L X0 X1 1 Y 2 Dx 1 (14.91 KiB) Viewed 32 times
f(x)=2−∣x∣ x∈[−2,2] . L=∫x0x11+(y′)2dx=
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f(x)=2−∣x∣ x∈[−2,2] . L=∫x0x11+(y′)2dx=
f(x)=2−∣x∣ x∈[−2,2] . L=∫x0x11+(y′)2dx=
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