Use implicit differentiation to find y′ and then evaluate y′ at (2,6). 5x3−y2−4=0 y′=y′∣(2,6)= (Simplify your answer.)
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Use implicit differentiation to find y′ and then evaluate y′ at (2,6). 5x3−y2−4=0 y′=y′∣(2,6)= (Simplify your answer.)
Use implicit differentiation to find y′ and then evaluate y′ at (2,6). 5x3−y2−4=0 y′=y′∣(2,6)= (Simplify your answer.)
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