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y′=−x+y2+1(2x+arctan(y))(y2+1)1−(1+y2x)2x+atan(y) From the derivative, find the slope of the tangent line at the give
Posted: Thu Jul 14, 2022 4:28 pm
by answerhappygod
- Y X Y2 1 2x Arctan Y Y2 1 1 1 Y2x 2x Atan Y From The Derivative Find The Slope Of The Tangent Line At The Give 1 (43.88 KiB) Viewed 60 times
y′=−x+y2+1(2x+arctan(y))(y2+1)1−(1+y2x)2x+atan(y) From the derivative, find the slope of the tangent line at the given point (−4π,1). y′=x−y2−1(1+y2)(−2x−arctany) m=π+8−2π8+π−2π Step 3 Using the slope and the given point (−4π,1), find the y-intercept of the line tangent to the given point. m=n+8−2n b=