y′=−x+y2+1(2x+arctan(y))(y2+1)​1−(1+y2x​)2x+atan(y)​ From the derivative, find the slope of the tangent line at the give

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answerhappygod
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y′=−x+y2+1(2x+arctan(y))(y2+1)​1−(1+y2x​)2x+atan(y)​ From the derivative, find the slope of the tangent line at the give

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Y X Y2 1 2x Arctan Y Y2 1 1 1 Y2x 2x Atan Y From The Derivative Find The Slope Of The Tangent Line At The Give 1
Y X Y2 1 2x Arctan Y Y2 1 1 1 Y2x 2x Atan Y From The Derivative Find The Slope Of The Tangent Line At The Give 1 (43.88 KiB) Viewed 59 times
y′=−x+y2+1(2x+arctan(y))(y2+1)​1−(1+y2x​)2x+atan(y)​ From the derivative, find the slope of the tangent line at the given point (−4π​,1). y′=x−y2−1(1+y2)(−2x−arctany)​ m=π+8−2π​8+π−2π​ Step 3 Using the slope and the given point (−4π​,1), find the y-intercept of the line tangent to the given point. m=n+8−2n​ b=
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