Find an equation of the tangent line to the graph of the equation at the given point. x2+xarctany=y−1,(−4π,1) Step 1 Us
Posted: Thu Jul 14, 2022 4:27 pm
Find an equation of the tangent line to the graph of the equation at the given point. x2+xarctany=y−1,(−4π,1) Step 1 Use implicit differentiation to find y′. x2+xarctany=y−1 5x+ +1+y2xy′=y′(1−1+y2x)y′=