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Find an equation of the tangent line to the graph of the equation at the given point. x2+xarctany=y−1,(−4π,1) Step 1 Us
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Find an equation of the tangent line to the graph of the equation at the given point. x2+xarctany=y−1,(−4π,1) Step 1 Us
Find an equation of the tangent line to the graph of the equation at the given point. x2+xarctany=y−1,(−4π,1) Step 1 Use implicit differentiation to find y′. x2+xarctany=y−1 5x+ +1+y2xy′=y′(1−1+y2x)y′=
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