Figure out these antiderivatives. 2) ∫1+y24dy 3) ∫4cos(u)(3sin(u)−2)−5du =∫cos(0)4(3sin(0)−2)−5du=−5−3∫coscos4(3sin(u)
Posted: Thu Jul 14, 2022 4:25 pm
Figure out these antiderivatives. 2) ∫1+y24dy 3) ∫4cos(u)(3sin(u)−2)−5du =∫cos(0)4(3sin(0)−2)−5du=−5−3∫coscos4(3sin(u)−a)−5=−43∫3cos(0)(−4)(3sin(0)−2)−5du=−1/3(3sin(0)−2)−4+c 4) ∫(5m−3)−1dm 5) ∫xln(3x)dx 6) ∫tt2−5t+3dt 7) ∫1+y2ydy 8) ∫6tan(3k)dk 65tan(34)dK 6∫sin(3x)dx cos(3ω)sin(y)(−sin200)a=(−y3 intokes y(6) =−1/314=−2
9). ∫(3x)2+11dx 10) ∫(3x)2+15xdx 11) ∫1−x2xdx 12) ∫1+x2arctan(x)dx 13) ∫2x(ln(x))3dx 14) ∫extan(ex)dx
9). ∫(3x)2+11dx 10) ∫(3x)2+15xdx 11) ∫1−x2xdx 12) ∫1+x2arctan(x)dx 13) ∫2x(ln(x))3dx 14) ∫extan(ex)dx