Figure out these antiderivatives. 2) ∫1+y24​dy 3) ∫4cos(u)(3sin(u)−2)−5du =∫cos(0)4(3sin(0)−2)−5du=−5−3​∫coscos4(3sin(u)

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answerhappygod
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Figure out these antiderivatives. 2) ∫1+y24​dy 3) ∫4cos(u)(3sin(u)−2)−5du =∫cos(0)4(3sin(0)−2)−5du=−5−3​∫coscos4(3sin(u)

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Figure Out These Antiderivatives 2 1 Y24 Dy 3 4cos U 3sin U 2 5du Cos 0 4 3sin 0 2 5du 5 3 Coscos4 3sin U 1
Figure Out These Antiderivatives 2 1 Y24 Dy 3 4cos U 3sin U 2 5du Cos 0 4 3sin 0 2 5du 5 3 Coscos4 3sin U 1 (17.99 KiB) Viewed 41 times
Figure Out These Antiderivatives 2 1 Y24 Dy 3 4cos U 3sin U 2 5du Cos 0 4 3sin 0 2 5du 5 3 Coscos4 3sin U 2
Figure Out These Antiderivatives 2 1 Y24 Dy 3 4cos U 3sin U 2 5du Cos 0 4 3sin 0 2 5du 5 3 Coscos4 3sin U 2 (13.49 KiB) Viewed 41 times
Figure out these antiderivatives. 2) ∫1+y24​dy 3) ∫4cos(u)(3sin(u)−2)−5du =∫cos(0)4(3sin(0)−2)−5du=−5−3​∫coscos4(3sin(u)−a)−5=−43​∫3cos(0)(−4)(3sin(0)−2)−5du=−1/3(3sin(0)−2)−4+c​ 4) ∫(5m−3)−1​dm 5) ∫xln(3x)​dx 6) ∫tt2−5t+3​dt 7) ∫1+y2y​dy 8) ∫6tan(3k)dk 65tan(34)dK 6∫sin(3x)dx cos(3ω)sin(y)​(−sin200)a​=(−y3​ intokes y(6) =−1/314​=−2
9). ∫(3x)2+11​dx 10) ∫(3x)2+15x​dx 11) ∫1−x2​x​dx 12) ∫1+x2arctan(x)​dx 13) ∫2x(ln(x))3​dx 14) ∫extan(ex)dx
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