(1 point) Using the method of substitution, \[ I=\int_{0}^{1} x^{2} \sqrt{6 x+7} d x=\int_{a}^{b} f(u) d u \] where \[ u
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(1 point) Using the method of substitution, \[ I=\int_{0}^{1} x^{2} \sqrt{6 x+7} d x=\int_{a}^{b} f(u) d u \] where \[ u
(1 point) Using the method of substitution, I=∫01x26x+7dx=∫abf(u)du where u= du= dx a=
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