x→3lim​x2−x−6x−3​= (a.) 0 , because the Limit of numerator is 0 (b.) 0 , because the Limit of denominator is 0 . (c.) 51

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answerhappygod
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x→3lim​x2−x−6x−3​= (a.) 0 , because the Limit of numerator is 0 (b.) 0 , because the Limit of denominator is 0 . (c.) 51

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X 3lim X2 X 6x 3 A 0 Because The Limit Of Numerator Is 0 B 0 Because The Limit Of Denominator Is 0 C 51 1
X 3lim X2 X 6x 3 A 0 Because The Limit Of Numerator Is 0 B 0 Because The Limit Of Denominator Is 0 C 51 1 (30.15 KiB) Viewed 40 times
x→3lim​x2−x−6x−3​= (a.) 0 , because the Limit of numerator is 0 (b.) 0 , because the Limit of denominator is 0 . (c.) 51​, because the Limit of numerator and denominator are 0 , so simplification is 1 (d.) 51​, because the Limit of numerator is 1 , and the Limit of denominator is 5 . (e.) DNE, because the Limit of numerator is 0 , and the Limit of denominator is 0 .
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