- Evaluate Yzdv Over The Region In The First Octant Inside X2 Y2 2x 0 X2 Y2 Z2 4 4 5 1 (7.22 KiB) Viewed 30 times
x2+y2+z2=4
4/5
Evaluate ∭yzdV over the region in the first octant, inside x2+y2−2x=0 x2+y2+z2=4 4/5
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Evaluate ∭yzdV over the region in the first octant, inside x2+y2−2x=0 x2+y2+z2=4 4/5
Evaluate ∭yzdV over the region in the first octant, inside x2+y2−2x=0
x2+y2+z2=4
4/5
x2+y2+z2=4
4/5
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