∫tan53xsec63xdx​=∫tan43xsec53xtan3xsec3xdx=∫{ ITEME1 sec53xtan3xsec3xdx=∫(ITEME2)sec53xtan3xsec3xdx=∫(ITEME3}sec53xtan3x

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answerhappygod
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∫tan53xsec63xdx​=∫tan43xsec53xtan3xsec3xdx=∫{ ITEME1 sec53xtan3xsec3xdx=∫(ITEME2)sec53xtan3xsec3xdx=∫(ITEME3}sec53xtan3x

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Tan53xsec63xdx Tan43xsec53xtan3xsec3xdx Iteme1 Sec53xtan3xsec3xdx Iteme2 Sec53xtan3xsec3xdx Iteme3 Sec53xtan3x 1
Tan53xsec63xdx Tan43xsec53xtan3xsec3xdx Iteme1 Sec53xtan3xsec3xdx Iteme2 Sec53xtan3xsec3xdx Iteme3 Sec53xtan3x 1 (16.89 KiB) Viewed 40 times
Tan53xsec63xdx Tan43xsec53xtan3xsec3xdx Iteme1 Sec53xtan3xsec3xdx Iteme2 Sec53xtan3xsec3xdx Iteme3 Sec53xtan3x 2
Tan53xsec63xdx Tan43xsec53xtan3xsec3xdx Iteme1 Sec53xtan3xsec3xdx Iteme2 Sec53xtan3xsec3xdx Iteme3 Sec53xtan3x 2 (20.69 KiB) Viewed 40 times
Tan53xsec63xdx Tan43xsec53xtan3xsec3xdx Iteme1 Sec53xtan3xsec3xdx Iteme2 Sec53xtan3xsec3xdx Iteme3 Sec53xtan3x 3
Tan53xsec63xdx Tan43xsec53xtan3xsec3xdx Iteme1 Sec53xtan3xsec3xdx Iteme2 Sec53xtan3xsec3xdx Iteme3 Sec53xtan3x 3 (24.41 KiB) Viewed 40 times
∫tan53xsec63xdx​=∫tan43xsec53xtan3xsec3xdx=∫{ ITEME1 sec53xtan3xsec3xdx=∫(ITEME2)sec53xtan3xsec3xdx=∫(ITEME3}sec53xtan3xsec3xdx=∫sec93xtan3xsec3xdx−2∫sec73xtan3xsec3xdx+∫sec53xtan3xsec3xdx[ Let u=sec3x=∫u93du​+(ITEME4)=10sec103x​+(ITEME6}+{ITEME7)+C​
∫cot5(32x​)csc7(32x​)dx=∫cot(32x​)csc(32x​)dx =∫(IEMF2)cot(32x​)csc(32x​)dx =∫(ITEMB3)csc6(32x​)cot(32x​)csc(32x​)dx =∫[ [TIM F4] csc6(32x​)cot(32x​)csc(32x​)dx =∫csc10(32x​)cot(32x​)csc(32x​)dx+(ITEMF5)+∫csc6(32x​)cot(32x​)csc(32x​)dx Let u=csc(32x​) [ITM F6] =∫u10(2−3du​)−2∫u8(2−3du​)+∫u6(2−3du​) =(2−3​)(11u11​)+2(23​)(9u9​)−(23​)(7u7​)+C ={TTEMF7}+{ITEMFB}+{ITEMF9}+C
∫sin33xcos53xdx=∫{ITEMD1}dx =∫({ITEMD2})cos53xsin3xdx =∫cos53xsin3xdx−∫cos73xsin3xdx Let u=cos3x dxdu​={ITEMD3} {ITEMD4}=sin3xdx =∫u5(3−du​)−∫u7(3−du​) ={ITEMD5} ={ITEMD6}+{ITEMD7}+C
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