Let p(z)=z5−5z4+13z3−25z2+36z−20 i) The remainder when p(z) is divided by z−i is equal to 영욤 and the remainder when p(z)

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Let p(z)=z5−5z4+13z3−25z2+36z−20 i) The remainder when p(z) is divided by z−i is equal to 영욤 and the remainder when p(z) is divided by z−1 is equal to 回 (a reminder: i is represented by I in maple). ii) You are given that that z=2i is root of p(z). Without doing any further calculation, we can deduce that another imaginary root of p(z) is z= a iii) Using the previous parts of the question or otherwise, we can factor p(z) into real linear and real quadratic factors in the form p(z)=(z+a)(z2+b)(z2+cz+d). where a,b,c,d∈R. The values of the constants can be determined to be a= Q,b= c= Q , and d=