- A Cable Is Suspended Between Two Points A And B 100 M Apart Horizontally B Is 5 M Higher Than A The Lowest Point In T 1 (139.52 KiB) Viewed 36 times
A cable is suspended between two points, A and B,100 m apart horizontally. B is 5 m higher than A. The lowest point in t
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A cable is suspended between two points, A and B,100 m apart horizontally. B is 5 m higher than A. The lowest point in t
A cable is suspended between two points, A and B,100 m apart horizontally. B is 5 m higher than A. The lowest point in the cable, C, is 40 m horizontally from A. (a) Calculate the maximum tensions in the cable if it carries a uniformly distributed load of 4kN/m over the whole span. (b) Calculate the maximum tensions in the cable if, in addition to the load in (a), a concentrated load of 50kN is attached at C, causing it to sag 5 m below A. Also find the minimum cable gradient at C. (c) Taking the tension in the cable at A as 1000kN and the cable slope as 15∘, determine the reaction at A if the cable passes over (i) a saddle, (ii) a pulley there to form a backstay at 30∘ to the horizontal. [835,2kN;800,0kN;896,5kN;857,4kN,1,52∘. (i) 816,5kN (ii) 765kN;7,5∘]
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